**A number is divisible by ***2*** if…**

it **ends** in 0, 2, 4, 6 or 8

e.g. 10, 2002, 1008…

**A number is divisible by ***3*** if…**

the **sum** of its digits is a multiple of 3

e.g. 1002 (1 + 0 +0 + 2 = 3 and 3 is a multiple of 3), 31008 (the digits add up to 12 and 12 is a multiple of 3)

**A number is divisible by ***4*** if…**

the **last two digits** are a multiple of 4

e.g. 10020 (the last two digits are 2 and 0. Twenty is a multiple of 4), 61008 (08, or eight, is a multiple of 4)

**A number is divisible by ***7*** if…**

Okay, this one is a bit **confusing**. Take the last digit and double it. **Subtract** this number from the remaining digits. If you get 0 or a number **divisible** by 7, the original number is divisible by 7.

e.g. 1008 (double 8 is 16. 100 – 16 = 84. 84 is divisible by 7, so 1008 is too), 203 (double 3 is 6. 20 – 6 = 14. 14 is divisible by 7, so 203 is too)

**A number is divisible by ***10*** if…**

it **ends** in 0

e.g. 100, 20, 250…

Try writing a **really** long random number (at least 5 digits!) and check if it’s **divisible** by each number from 1 to 10.

Tell us your results in the **comments** below!

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